Every transcendental operator has a non-trivial invariant subspace

Simple item page
dc.creatorKim, Yun-Su
dc.date2009-01-25
dc.date2009-01-30
dc.date.accessioned2026-07-07T12:35:29Z
dc.date.available2026-07-07T12:35:29Z
dc.descriptionIn this paper, to solve the invariant subspace problem, contraction operators are classified into three classes ; (Case 1) completely non-unitary contractions with a non-trivial algebraic element, (Case 2) completely non-unitary contractions without a non-trivial algebraic element, or (Case 3) contractions which are not completely non-unitary. We know that every operator of (Case 3) has a non-trivial invariant subspace. In this paper, we answer to the invariant subspace problem for the operators of (Case 2). Since (Case 1) is simpler than (Case 2), we leave as a question.
dc.identifierhttps://arxiv.org/abs/0901.3852
dc.identifierhttp://arxiv.org/abs/0901.3852
dc.identifier.urihttp://salesiana.dossiersoluciones.com/handle/123456789/217782
dc.subjectGeneral Mathematics
dc.subject47A15; 47S99
dc.titleEvery transcendental operator has a non-trivial invariant subspace
dc.typetext

Files

Collections

arXiv