A proof of Higgins' conjecture
| dc.creator | Braun, Gabor | |
| dc.date | 2003-12-06 | |
| dc.date | 2004-09-05 | |
| dc.date.accessioned | 2026-07-07T05:03:37Z | |
| dc.date.available | 2026-07-07T05:03:37Z | |
| dc.description | Let f: G=* G(i) -> B=* B(i) be a group homomorphism between free products of groups. Suppose that G(i)f=B(i) of all i. Let H be a subgroup of G such that Hf=B. Then H decomposes into a free product H=*H(i) with H(i)f=B(i). Furthermore, H(i) decomposes into a free product of a free group and the intersection of H(i) with some conjugate of G(i). Higgins conjectured this in 1971 and now we prove it. | |
| dc.description | 6 pages; corrected typos; added journal-ref, MSC-class 20L05; bibliography converted to amsrefs format | |
| dc.identifier | https://arxiv.org/abs/math/0312139 | |
| dc.identifier | http://arxiv.org/abs/math/0312139 | |
| dc.identifier | Bull. Austral. Math. Soc., Vol. 70 (2004) [207-212] | |
| dc.identifier.uri | http://salesiana.dossiersoluciones.com/handle/123456789/69493 | |
| dc.subject | Group Theory | |
| dc.subject | 20E06; 20L05 | |
| dc.title | A proof of Higgins' conjecture | |
| dc.type | text |