On the field of differential rational invariants of a subgroup of affine group (Ordinary differential case)
| dc.creator | Bekbaev, Ural | |
| dc.date | 2006-08-19 | |
| dc.date.accessioned | 2026-07-07T07:21:56Z | |
| dc.date.available | 2026-07-07T07:21:56Z | |
| dc.description | An ordinary differential field $(F,d)$ of characteristic zero, a subgroup $H$ of affine group $ GL(n,C)\propto C^n$ with respect to its identical representation in $F^n$ and the following two fields of differential rational functions in $x=(x_1,x_2,...,x_n)$-column vector, $$C< x, d>^H=\{f^d< x> \in C< x, d> : f^d< hx+ h_0> = f^d< x> {for any} (h,h_0)\in H \},$$ $$C< x, d>^{(F^*,H)}=\{f^d< x> \in C< x, d> : f^{g^{-1}d}< hx+ h_0> = f^d< x> {for any} g\in F^* {and} (h,h_0)\in H \}$$ are considered, where $C$ is the constant field of $(F,d)$ and $C< x, d>$ is the field of differential rational functions in $x_1,x_2,...,x_n$ over $C$. The field $C< x, d>^H$ ($C< x, d>^{(F^*,H)}$) is an important tool in the equivalence problem of paths(respect. curves) in Differential Geometry with respect to the motion group $H$. In this paper an pure algebraic approach is offered to describe these fields. The field $C< x, d>^{(F^*,H)}$ and its relation with $C< x, d>^H$ are investigated. It is shown also that $C< x, d>^H$ can be derived from some algebraic (without derivatives) invariants of $H$. Key words: Differential field, differential rational function, invariant, differential transcendent degree. 2000 Mathematics Subject Classification: 12H05, 53A04, 53A55 | |
| dc.identifier | https://arxiv.org/abs/math/0608479 | |
| dc.identifier | http://arxiv.org/abs/math/0608479 | |
| dc.identifier.uri | http://salesiana.dossiersoluciones.com/handle/123456789/115480 | |
| dc.subject | Algebraic Geometry | |
| dc.subject | Differential Geometry | |
| dc.subject | 20H05, 53A04, 53A55 | |
| dc.title | On the field of differential rational invariants of a subgroup of affine group (Ordinary differential case) | |
| dc.type | text |