Spectrum of a weakly hypercyclic operator meets the unit circle

Simple item page
dc.creatorDilworth, S. J.
dc.creatorTroitsky, Vladimir G.
dc.date2002-08-24
dc.date.accessioned2026-07-07T04:50:23Z
dc.date.available2026-07-07T04:50:23Z
dc.descriptionIt is shown that every component of the spectrum of a weakly hypercyclic operator meets the unit circle. The proof is based on the lemma that a sequence of vectors in a Banach space whose norms grow at geometrical rate doesn't have zero in its weak closure.
dc.description3 pages, to appear in Proceedings of the Conference "Trends in Banach Spaces and Operator Theory", Memphis, 2001
dc.identifierhttps://arxiv.org/abs/math/0208193
dc.identifierhttp://arxiv.org/abs/math/0208193
dc.identifier.urihttp://salesiana.dossiersoluciones.com/handle/123456789/64774
dc.subjectFunctional Analysis
dc.subject47A16; 47A10; 47A25
dc.titleSpectrum of a weakly hypercyclic operator meets the unit circle
dc.typetext

Files

Collections

arXiv