There is no $κ(900)$

dc.creatorCherry, S. N.
dc.creatorPennington, M. R.
dc.date2000-05-21
dc.date2000-11-27
dc.date.accessioned2026-07-07T10:32:39Z
dc.date.available2026-07-07T10:32:39Z
dc.descriptionIn the I=0 sector there are more scalar mesons than can fit in one $q{\bar q}$ nonet. Consequently, many have claimed that there is in fact more than one multiplet, perhaps both $q{\bar q}$ and $qq{\bar {qq}}$. Such proposals require the existence of at least two strange isodoublets (and their antiparticles). The current PDG Tables list just one state, the $K^*_0(1430)$, while fits to data with Breit-Wigner forms and variable backgrounds can accommodate a $κ(900)$ too. Whether a state exists in the spectrum of hadrons is not a matter of ability to fit data along the real energy axis, but is completely specified by the number of poles in the complex energy plane. Here we perform a model-independent analytic continuation of $πK$ scattering results between 825 MeV and 2 GeV to determine the number and position of resonance poles. We find that there {\bf is} a $K^*_0(1430)$, but {\bf no} $κ(900)$. The LASS data cannot rule out the possibility of a very low mass $κ$ well below 825 MeV.
dc.description19 pages, 5 figures Version to be published in Nuclear Physics A containing new figures and additional entries in tables to clarify the role played by near threshold $πK$ scattering$ below the energy explored by the SLAC LASS experiment
dc.identifierhttps://arxiv.org/abs/hep-ph/0005208
dc.identifierhttp://arxiv.org/abs/hep-ph/0005208
dc.identifierNucl.Phys.A688:823-841,2001
dc.identifierdoi:10.1016/S0375-9474(00)00587-X
dc.identifier.urihttp://salesiana.dossiersoluciones.com/handle/123456789/178827
dc.subjectHigh Energy Physics - Phenomenology
dc.titleThere is no $κ(900)$
dc.typetext

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