Is There a Unified Description of Conductivity of Layered Cuprates ?

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dc.creatorAlmasan, C. C.
dc.creatorCimpoiasu, E.
dc.creatorLevin, G. A.
dc.creatorZheng, H.
dc.creatorPaulikas, A. P.
dc.creatorVeal, B. W.
dc.date1999-08-16
dc.date1999-08-23
dc.date.accessioned2026-07-07T03:14:15Z
dc.date.available2026-07-07T03:14:15Z
dc.descriptionWe present a novel approach to the analysis of the normal state in-plane $σ_{ab}$ and out-of-plane $σ_{c}$ conductivities of anisotropic layered crystals such as oxygen deficient $YBa_{2}Cu_{3}O_{x}$. It can be shown that the resistive anisotropy is determined by the ratio of the phase coherence lengths in the respective directions; i.e., $σ_{ab}/σ_c=\ell_{ab}^2/\ell_c^2$. From the idea that at all doping levels and temperatures $T$ the out-of-plane transport in these crystals is incoherent, follows that $\ell_c$ is T-independent, equal to the spacing $\ell_0$ between the neighboring bilayers. Thus, the T-dependence of $\ell_{ab}$ is given by the measured anisotropy, and $σ_{ab}(\ell_{ab})$ dependence is obtained by plotting $σ_{ab}$ vs $\ell=(σ_{ab}/σ_c)^{1/2}\ell_0$. The analysis of several single crystals of $YBa_{2}Cu_{3}O_{x}$ ($6.35<x<6.93$) shows that for all of them $σ_{ab}(\ell)$ is described by a universal dependence $σ_{ab}/\barσ=f(\ell/\bar\ell)$ with doping dependent parameters $\barσ$ and $\bar\ell$.
dc.description5 pages, 2 figures. To be published in J. Low Temp. Phys. Proceedings of MOS-99, Stockholm. Prompted by inquiries from readers, several clarifications are introduced: Temperature range over which data were taken is indicated; a misleading typo in the sentence at the bottom of page 3 is corrected; a few minor grammatical changes have been made
dc.identifierhttps://arxiv.org/abs/cond-mat/9908233
dc.identifierhttp://arxiv.org/abs/cond-mat/9908233
dc.identifier.urihttp://salesiana.dossiersoluciones.com/handle/123456789/29600
dc.subjectStrongly Correlated Electrons
dc.subjectSuperconductivity
dc.titleIs There a Unified Description of Conductivity of Layered Cuprates ?
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