The degree of the bicanonical map of a surface with $p_g=0$
| dc.creator | Lopes, Margarida Mendes | |
| dc.creator | Pardini, Rita | |
| dc.date | 2005-05-11 | |
| dc.date | 2006-02-14 | |
| dc.date.accessioned | 2026-07-07T06:39:56Z | |
| dc.date.available | 2026-07-07T06:39:56Z | |
| dc.description | In this note it is shown that, given a smooth minimal complex surface of general type S with p_g(S)=0, K^2_S=3, for which the bicanonical map is a morphism, then the degree of the bicanonical map of S is not equal to 3. This completes our earlier results, showing that if X is a minimal surface of general type with p_g=0, K^2>=3 such that |2K_X| is free, then the bicanonical map of X can have degree 1, 2 or 4. | |
| dc.description | Final version to appear in Proceedings of the AMS | |
| dc.identifier | https://arxiv.org/abs/math/0505231 | |
| dc.identifier | http://arxiv.org/abs/math/0505231 | |
| dc.identifier.uri | http://salesiana.dossiersoluciones.com/handle/123456789/101263 | |
| dc.subject | Algebraic Geometry | |
| dc.subject | 14J29 | |
| dc.title | The degree of the bicanonical map of a surface with $p_g=0$ | |
| dc.type | text |