There may be no Hausdorff ultrafilters
| dc.creator | Bartoszynski, Tomek | |
| dc.creator | Shelah, Saharon | |
| dc.date | 2003-11-05 | |
| dc.date.accessioned | 2026-07-07T05:02:38Z | |
| dc.date.available | 2026-07-07T05:02:38Z | |
| dc.description | An ultrafilter U is Hausdorff if for any two functions f,g mapping N to N, f(U)=g(U) iff f(n)=g(n) for n in some X in U. We will show that it is consistent that there are no Hausdorff ultrafilters. | |
| dc.identifier | https://arxiv.org/abs/math/0311064 | |
| dc.identifier | http://arxiv.org/abs/math/0311064 | |
| dc.identifier | in: {Logic Colloquium 2004} (2008) 18--32 | |
| dc.identifier.uri | http://salesiana.dossiersoluciones.com/handle/123456789/69084 | |
| dc.subject | Logic | |
| dc.title | There may be no Hausdorff ultrafilters | |
| dc.type | text |