A PL-manifold of nonnegative curvature homeomorphic to $S^2 \times S^2$ is a direct metric product (Preliminary version)

dc.creatorOrshanskiy, Sergey
dc.date2008-07-11
dc.date2008-07-31
dc.date.accessioned2026-07-07T09:53:39Z
dc.date.available2026-07-07T09:53:39Z
dc.descriptionLet $M^4$ be a PL-manifold of nonnegative curvature that is homeomorphic to a product of two spheres, $S^2 \times S^2$. We prove that $M$ is a direct metric product of two spheres endowed with some polyhedral metrics. In other words, $M$ is a direct metric product of the surfaces of two convex polyhedra in $\mathbb{R}^3$. The background for the question is the following. The classical H.Hopf's hypothesis states: for any Riemannian metric on $S^2 \times S^2$ of nonnegative sectional curvature the curvature cannot be strictly positive at all points. There is no quick answer to this question: it is known that a Riemannian metric on $S^2 \times S^2$ of nonnegative sectional curvature need not be a product metric. However, M.Gromov has pointed out that the condition of nonnegative curvature in the PL-case appears to be stronger than nonnegative sectional curvature of Riemannian manifolds and analogous to some condition on the curvature operator. So the motivation for the question addressed in this text is to settle the PL-version of the Hopf's hypothesis.
dc.description15 pages
dc.identifierhttps://arxiv.org/abs/0807.1922
dc.identifierhttp://arxiv.org/abs/0807.1922
dc.identifier.urihttp://salesiana.dossiersoluciones.com/handle/123456789/166028
dc.subjectDifferential Geometry
dc.subject53C15; 57Q25
dc.titleA PL-manifold of nonnegative curvature homeomorphic to $S^2 \times S^2$ is a direct metric product (Preliminary version)
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