Exceptional divisors which are not uniruled belong to the image of the Nash map

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We prove that, if X is a variety over an uncountable algebraically closed field k of characteristic zero, then any irreducible exceptional divisor E on a resolution of singularities of X which is not uniruled, belongs to the image of the Nash map, i.e. corresponds to an irreducible component of the space of arcs on X centered in Sing X. This reduces the Nash problem of arcs to understanding which uniruled essential divisors are in the image of the Nash map, more generally, how to determine the uniruled essential divisors from the space of arcs.
14 pages

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Algebraic Geometry, 14B05, 14E15, 14J17, 32S05, 32S45

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http://salesiana.dossiersoluciones.com/handle/123456789/174257

Consulte el texto completo en el siguiente enlace:

https://arxiv.org/abs/0811.2421
 http://arxiv.org/abs/0811.2421

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arXiv