Solving the Puzzle of ${M_{D^*}-M_{D}\over M_{D_s^*}-M_{D_s}}$ $\simeq$ ${M_{B^*}-M_{B}\over M_{B_s^*}-M_{B_s}}$ $\simeq$ $1$

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dc.creatorHwang, Dae Sung
dc.creatorKim, Gwang-Hee
dc.date1997-01-15
dc.date.accessioned2026-07-07T04:01:10Z
dc.date.available2026-07-07T04:01:10Z
dc.descriptionThe commonly used Hamiltonian of the chromomagnetic hyperfine splitting is inversely proportional to the product of the masses of two constituent quarks composing the meson. So it is expected to have $(M_{D^*}-M_{D})/(M_{D_s^*}-M_{D_s})$ $\simeq$ $(M_{B^*}-M_{B})/(M_{B_s^*}-M_{B_s})$ $\simeq$ $1.6$, when the constituent quark masses $m_{u,d}=0.33$ GeV and $m_s=0.53$ GeV are used. However, the experimental results show that the above ratios are very close to 1. We solve this puzzle by employing the Hamiltonian recently proposed by Scora and Isgur.
dc.description10 pages, Latex, 5 figures
dc.identifierhttps://arxiv.org/abs/hep-ph/9701295
dc.identifierhttp://arxiv.org/abs/hep-ph/9701295
dc.identifier.urihttp://salesiana.dossiersoluciones.com/handle/123456789/46798
dc.subjectHigh Energy Physics - Phenomenology
dc.titleSolving the Puzzle of ${M_{D^*}-M_{D}\over M_{D_s^*}-M_{D_s}}$ $\simeq$ ${M_{B^*}-M_{B}\over M_{B_s^*}-M_{B_s}}$ $\simeq$ $1$
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