A note on primes dividing alternating sums

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We define A_n=\sum_{i=1}^n (-1)^i\frac{1}{i} and we show that, for every prime p, there exists a number n such that A_n\equiv 0 (mod p).

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General Mathematics

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http://salesiana.dossiersoluciones.com/handle/123456789/115049

Consulte el texto completo en el siguiente enlace:

https://arxiv.org/abs/math/0607491
 http://arxiv.org/abs/math/0607491

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arXiv