Geometric Realizations of Hermitian curvature models

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We show that a Hermitian algebraic curvature model satisfies the Gray identity if and only if it is geometrically realizable by a Hermitian manifold. Furthermore, such a curvature model can in fact be realized by a Hermitian manifold of constant scalar curvature and constant *-scalar curvature which satisfies the Kaehler condition at the point in question.

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Differential Geometry, 53B20

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http://salesiana.dossiersoluciones.com/handle/123456789/210682

Consulte el texto completo en el siguiente enlace:

https://arxiv.org/abs/0812.2743
 http://arxiv.org/abs/0812.2743

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arXiv