Novikov operad is not Koszul

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An algebra with identities $a\circ(b\circ c-c\circ b)=(a\circ b)\circ c-(a\circ c)\circ b$ and $a\circ(b\circ c)=b\circ(a\circ c)$ is called Novikov. We show that Novikov operad is not Koszul.
5 pages

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Rings and Algebras, 16R10; 17A50; 17A30; 17D25; 17C50

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http://salesiana.dossiersoluciones.com/handle/123456789/221104

Consulte el texto completo en el siguiente enlace:

https://arxiv.org/abs/0902.3771
 http://arxiv.org/abs/0902.3771

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arXiv