Complexity of Inverting the Euler Function

dc.creatorContini, Scott
dc.creatorCroot, Ernie
dc.creatorShparlinski, Igor
dc.date2004-04-06
dc.date2004-04-23
dc.date.accessioned2026-07-07T05:07:11Z
dc.date.available2026-07-07T05:07:11Z
dc.descriptionWe present an algorithm to invert the Euler function $ϕ(m)$. The algorithm, for a given $n \geq 1$, in polynomial time ``on average'', finds the set $Ψ(n)$ of all solutions $m$ to $ϕ(m) = n$. In fact, in the worst case, $Ψ(n)$ is exponentially large, and cannot be computed in polynomial time. In the opposite direction, we show, under a widely accepted number theoretic conjecture, that there is a polynomial time reduction of the Partition Problem, an NP-complete problem, to the problem of deciding whether $ϕ(m) = n$ has a solution for a small set of integers n. This shows that the problem of deciding whether a given finite set of integers S contains a totient is NP-complete. A totient is an integer n that lies in the image of the phi function; that is, an integer n for which there exists an integer m solving phi(m) = n. Finally, we establish close links between of inverting the Euler function and the integer factorization problem.
dc.descriptionSlight restatement of results in introduction and in section 4
dc.identifierhttps://arxiv.org/abs/math/0404116
dc.identifierhttp://arxiv.org/abs/math/0404116
dc.identifier.urihttp://salesiana.dossiersoluciones.com/handle/123456789/70761
dc.subjectNumber Theory
dc.subject11Y16
dc.titleComplexity of Inverting the Euler Function
dc.typetext

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