The determinant of $AA^*-A^*A$ for a Leonard pair $A,A^*$

dc.creatorNomura, Kazumasa
dc.creatorTerwilliger, Paul
dc.date2005-11-26
dc.date.accessioned2026-07-07T06:51:45Z
dc.date.available2026-07-07T06:51:45Z
dc.descriptionLet $K$ denote a field, and let $V$ denote a vector space over $K$ with finite positive dimension. We consider a pair of linear transformations $A:V \to V$ and $A^*: V \to V$ that satisfy (i), (ii) below: (i) There exists a basis for $V$ with respect to which the matrix representing $A$ is irreducible tridiagonal and the matrix representing $A^*$ is diagonal. (ii) There exists a basis for $V$ with respect to which the matrix representing $A^*$ is irreducible tridiagonal and the matrix representing $A$ is diagonal. We call such a pair a {\em Leonard pair} on $V$. In this paper we investigate the commutator $AA^*-A^*A$. Our results are as follows. First assume the dimension of $V$ is even. We show $AA^*-A^*A$ is invertible and display several attractive formulae for the determinant. Next assume the dimension of $V$ is odd. We show that the null space of $AA^*-A^*A$ has dimension 1. We display a nonzero vector in this null space. We express this vector as a sum of eigenvectors for $A$ and as a sum of eigenvectors for $A^*$.
dc.description11 pages
dc.identifierhttps://arxiv.org/abs/math/0511641
dc.identifierhttp://arxiv.org/abs/math/0511641
dc.identifier.urihttp://salesiana.dossiersoluciones.com/handle/123456789/105092
dc.subjectRings and Algebras
dc.subjectCombinatorics
dc.subject15A15
dc.titleThe determinant of $AA^*-A^*A$ for a Leonard pair $A,A^*$
dc.typetext

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