A short proof of Grinshpon's theorem

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dc.creatorKhurana, Dinesh
dc.date2009-04-06
dc.date.accessioned2026-07-07T13:00:50Z
dc.date.available2026-07-07T13:00:50Z
dc.descriptionGrinshpon has proved that if $S$ is a commutative subring of a ring $R$ and $A\in M_n(S)$ is invertible in $M_n(R)$, then $det(A)$ is invertible in $R$. We give a very short proof of the result.
dc.description1 page
dc.identifierhttps://arxiv.org/abs/0904.0906
dc.identifierhttp://arxiv.org/abs/0904.0906
dc.identifier.urihttp://salesiana.dossiersoluciones.com/handle/123456789/225966
dc.subjectRings and Algebras
dc.titleA short proof of Grinshpon's theorem
dc.typetext

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