2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/116440Let $Y$ be a singular algebraic variety and let $\TY$ be a resolution of singularities of $Y$. Assume that the exceptional locus of $\TY$ over $Y$ is an irreducible divisor $\TZ$ in $\TY$. For every Lefschetz decomposition of $\TZ$ we construct a triangulated subcategory $\TD \subset \D^b(\TY)$ which gives a desingularization of $\D^b(Y)$. If the Lefschetz decomposition is generated by a vector bundle tilting over $Y$ then $\TD$ is a noncommutative resolution, and if the Lefschetz decomposition is rectangular, then $\TD$ is a crepant resolution.24 pages; the proof of the main theorem rewritten, a section on functoriality is addedAlgebraic GeometryRepresentation TheoryLefschetz decompositions and Categorical resolutions of singularitiestext