2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/45797The multi-flavor Schwinger model on $R^1$ at finite temperature $T$ is mathematically equivalent to the model on $S^1$ at $T=0$. The latter is reduced to a quantum mechanical system of $N-1$ degrees of freedom. Physics sensitively depends on the parameter $m/T$. Finite temperature behavior of the massive Schwinger model is quite different from that of the massless Schwinger model.9 pages, LaTex + 3 figures; uses epsf.sty; for the proceedings of Thermo95High Energy Physics - PhenomenologyHigh Energy Physics - Theorytext