2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/131826Let f(x) be a continuous function from a compact real interval into itself with a periodic orbit of minimal period m, where m is not an integral power of 2. Then, by Sharkovsky's theorem, for every positive integer n with m \prec n in the Sharkovsky's ordering defined below, a lower bound on the number of periodic orbits of f(x) with minimal period n is 1. Could we improve this lower bound from 1 to some larger number? In this paper, we give a complete answer to this question.11 pagesDynamical SystemsNumber Theory37E05 (Primary), 37C25, 37E15 (Secondary)text