A Fake $CP^2 #4 {\bar CP^2}$

2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/110159This paper is not ready for public consumption, as the last step (Figure 20) is incorrect.Geometric TopologyAlgebraic Geometry57R57, 14J26, 57R65A Fake $CP^2 #4 {\bar CP^2}$text