2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/69054If $X$ is an abelian variety over a field and $L$ is an invertible sheaf, we know that the degree of the 0-cycle $L^g$ is divisible by $g!$. As a 0-cycle, it is not, even over a field of cohomological dimension 1. But we show that over a finite field there is perhaps some hope.7 pagesAlgebraic GeometrySome elementary theorems about divisibility of 0-cycles on abelian varieties defined over finite fieldstext