2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/164114We consider the motion of a Brownian particle in $\mathbb{R}$, moving between a particle fixed at the origin and another moving deterministically away at slow speed $ε>0$. The middle particle interacts with its neighbours via a potential of finite range $b>0$, with a unique minimum at $a>0$, where $b<2a$. We say that the chain of particles breaks on the left- or right-hand side when the middle particle is greater than a distance $b$ from its left or right neighbour, respectively. We study the asymptotic location of the first break of the chain in the limit of small noise, in the case where $ε= ε(σ)$ and $σ>0$ is the noise intensity.13 pages, 2 figures. v2: Corrected a mistake in proof of second part of main theoremProbabilityMathematical Physics60J70text