2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/163268We prove that the jacobian of a hyperelliptic curve y^2=f(x) is absolutely simple if deg(f)=q+1 where q is a power prime congruent to 5 modulo 8, the polynomial f(x) is irreducible over the ground field of characteristic zero and its Galois group is L_2(q).LaTeX, 16 pagesAlgebraic GeometryNumber Theory14H40;14K05;11G30;11G10Endomorphism algebras of hyperelliptic jacobians and finite projective linestext