$μ$-complete Souslin trees on $μ^+$

2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/152810We prove that $μ=μ^{<μ}$, $2^μ=μ^+$ and ``there is a non reflecting stationary subset of $μ^+$ composed of ordinals of cofinality $<μ$'' imply that there is a $μ$-complete Souslin tree on $μ^+$.Logic$μ$-complete Souslin trees on $μ^+$text