2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/152065I exhibit a prequantization of the torus which is actually a ``full'' quantization in the sense that a certain complete set of classical observables is irreducibly represented. Thus in this instance there is no Groenewold-Van Hove obstruction to quantization.8 pages, AMS-LaTeXDifferential GeometryHigh Energy Physics - TheoryQuantum Physicstext