2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/216171It is shown, using sutured manifold theory, that if there are any 2-component counterexamples to the Generalized Property R Conjecture, then any knot of least genus among components of such counterexamples is not a fibered knot. The general question of what fibered knots might appear as a component of such a counterexample is further considered; much can be said about the monodromy of the fiber, particularly in the case in which the fiber is of genus two.18 pages, 4 figuresGeometric Topology57M25 (Primary), 57N13 (Secondary)Fibered knots and Property 2Rtext