2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/114046The main motivation here is a question: whether any polyhedron which can be subdivided into convex pieces without adding a vertex, and which has the same vertices as a convex polyhedron, is infinitesimally rigid. We prove that it is indeed the case for two classes of polyhedra: those obtained from a convex polyhedron by ``denting'' at most two edges at a common vertex, and suspensions with a natural subdivision.v2: same as v1 but with 2 figuresDifferential GeometryOn the infinitesimal rigidity of weakly convex polyhedratext