2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/95801We show that there is a measure $μ$, defined on the hyperbolic plane and with polynomial growth, such that the centered maximal operator associated to $μ$ does not satisfy weak type $(1,1)$ bounds.Classical Analysis and ODEs42B25An example on the maximal function associated to a nondoubling measuretext