2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/115049We define A_n=\sum_{i=1}^n (-1)^i\frac{1}{i} and we show that, for every prime p, there exists a number n such that A_n\equiv 0 (mod p).General MathematicsA note on primes dividing alternating sumstext