2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/94643Let G be an abelian group and let lambda be the smallest rank of any group whose direct sum with a free group is isomorphic to G. If lambda is uncountable, then G has lambda pairwise disjoint, non-free subgroups. There is an example where lambda is countably infinite and G does not have even two disjoint, non-free subgroups.LogicDisjoint Non-Free Subgoups of Abelian Groupstext