2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/26812Simple example: During the sudden expansion of an isolated ideal gas from a small volume V_0 into a larger one V_1, the entropy changes by Delta S= N ln(V_1/V_0)=-beta Delta F>0 but no work W is produced nor absorbed. Consequently, Jarzynski's identity <exp(-beta W)>= exp(-beta Delta F) is wrong.2 pages, no figureStatistical MechanicsFlaw of Jarzynski's equality when applied to systems with several degrees of freedomtext