2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/134246For a given blocklength we determine the number of interleavers which have spread equal to two. Using this, we find out the probability that a randomly chosen interleaver has spread two. We show that as blocklength increases, this probability increases but very quickly converges to the value $1-e^{-2} \approx 0.8647$. Subsequently, we determine a lower bound on the probability of an interleaver having spread at least $s$. We show that this lower bound converges to the value $e^{-2(s-2)^{2}}$, as the blocklength increases.5 pages, published in Proceedings of IEEE International Symposium on Information Theory 2005, Adelaide, AustraliaInformation Theorytext