2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/82532We discuss a general, exact (in that matrix elements are preserved) mapping of fermion pairs to bosons, and find a simple factorization of the boson representation of fermion operators. This leads to boson Hamiltonians that are Hermitian and finite, with no more than two-body operators if the fermion Hamiltonian has at most two-body operators, and one-body boson transition operators if the fermion transition operator is one-body.10 pages in RevTex with no figures, Los Alamos preprint # LA-UR-93:4013Nuclear Theorytext