2026-07-072026-07-07http://salesiana.dossiersoluciones.com/handle/123456789/149992Let $X$ be a non-singular projective complex surface. We can show that Bloch's conjecture (i.e., that if $p_g=0$ then the Albanese kernel vanishes) is equivalent to the following statement: If $p_g(X)=0$ then for any given Zariski open $U\subset X$ and $ω\in H^2(U,{\bf C})$ there is a smaller Zariski open $V\subset U$ such that $$ω\mid_V =ω'+ζ$$ where $ω'\in F^2H^2(V,{\bf C})$ and $ζ$ is integral.4 pages, LaTeXAlgebraic Geometrytext